UD type:
UD sub-type:
Unclear, revisit later
Texts
Help
Select a text:
Bibliography Select a chapter:
(no revisions)
Show parallels Show headlines
Use dependency labeler
Chapter id: 5936
- Click on a sentence to show its analysis
- Keep the mouse pointer over a lemma to show its meanings.
ādhyātmikāścatasras tuṣṭayaḥ / (1.1)
Par.?
adhyātmani bhavā ādhyātmikāstāśca prakṛtyupādānakālabhāgyākhyāḥ / (1.2)
Par.?
tatra prakṛtyākhyāḥ / (1.3)
Par.?
yathā kaścit prakṛtiṃ vetti tasyāḥ saguṇatvanirguṇatvaṃ ca / (1.4)
Par.?
tena tattvaṃ tatkāryaṃ vijñāyaiva kevalaṃ tuṣṭastasya nāsti mokṣaḥ / (1.5)
Par.?
eṣā prakṛtyākhyā / (1.6)
Par.?
upādānākhyā / (1.7)
Par.?
yathā kaścid avijñāyaiva tattvānyupādānagrahaṇaṃ karoti tridaṇḍakamaṇḍaluvividikābhyo mokṣa iti tasyāpi nāsti mokṣa iti / (1.8)
Par.?
eṣopādānākhyā / (1.9)
Par.?
tathā kālākhyā / (1.10)
Par.?
kālena mokṣo bhaviṣyatīti kiṃ tattvābhyāsenetyeṣa kālākhyā tuṣṭiḥ / (1.11) Par.?
tasya nāsti mokṣa iti / (1.12)
Par.?
tathā bhāgyākhyā / (1.13)
Par.?
bhāgyenaiva mokṣo bhaviṣyatīti bhāgyākhyā / (1.14)
Par.?
caturdhā tuṣṭir iti / (1.15)
Par.?
bāhyā viṣayoparamācca pañca / (1.16)
Par.?
bāhyāstuṣṭayaḥ pañcaviṣayoparamāt / (1.17)
Par.?
śabdasparśarūparasagandhebhya uparato 'rjanarakṣaṇakṣayasaṅgahiṃsādarśanāt / (1.18)
Par.?
vṛddhinimittaṃ paśupālyavāṇijyapratigrahasevāḥ kāryā etad arjanaṃ duḥkham / (1.19)
Par.?
arjitānāṃ rakṣaṇe duḥkham / (1.20)
Par.?
upabhogāt kṣīyata iti kṣayaduḥkham / (1.21)
Par.?
tathā viṣayopabhogasaṅge kṛte nāstīndriyāṇām upaśama iti saṅgadoṣaḥ / (1.22)
Par.?
tathā nānupahatya bhūtānyupabhoga iti hiṃsādoṣaḥ / (1.23)
Par.?
evam arjanādidoṣadarśanāt pañcaviṣayoparamāt pañca tuṣṭayaḥ / (1.24)
Par.?
evam ādhyātmikabāhyabhedān nava tuṣṭayaḥ / (1.25)
Par.?
tāsāṃ nāmāni śāstrāntare proktānyaṃbhaḥ salilam ogho vṛṣṭiḥ sutamaḥ pāraṃ sunetraṃ nārīkam anuttamāmbhasikam iti / (1.26)
Par.?
āsāṃ tuṣṭīnāṃ viparītā aśaktibhedād buddhivadhā bhavanti / (1.27)
Par.?
tad yathānambho 'salilam anogha ityādivaiparītyād buddhivadhā iti / (1.28)
Par.?
siddhir ucyate // (1.29)
Par.?
Duration=0.047234058380127 secs.